byteCoderNicomachus Theorem 1³ + 2³ + 3³ + ... + n³ = (1 + 2 + 3 + ... + n)² The sum of the first n cubes a
Nicomachus Theorem 1³ + 2³ + 3³ + ... + n³ = (1 + 2 + 3 + ... + n)² The sum of the first n cubes always equals the square of the sum of the first n integers. For n = 3: (1 + 2 + 3)² = 6² = 36 = 1 + 8 + 27 https://t.co/JX8ooaJQhh